- 【深基4.习9】打分
1
- 2024-4-12 16:47:34 @
#include <bits/stdc++.h> using namespace std; int main(){ int s=-100001,j=100001,n,m; double d=0,i,h; cin>>n; for(int i=1;i<=n;i++){ cin>>m; if(m>=s){ s=m; } if(m<=j){ j=m; } d=d+m; } h=d-s-j; n=n-2; d=h/n; printf("%.2lf",d ); return 0; }
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Information
- ID
- 658
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 5
- Tags
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- # Submissions
- 448
- Accepted
- 163
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