这个题目用到了数学消元推导，用公式 a+b+c =x 2a+3b+4c = y 利用a>=0,b>=0的关系推导出c的范围

#include<bits/stdc++.h>
using namespace std;
int main(){
	long long t,x,y,minn = 100006,maxn =0 ;
	cin>>t;
	for(int i = 1;i<=t;i++){
		cin>>x>>y;
		minn = 1e9,maxn =0;//注意min的范围取值 
		if(y/2-x>=maxn) maxn = y/2-x;
		if(y-3*x<=minn){//y-3x有可能是小于0
				minn = y-3*x;
		}
		if(minn<0) minn = 0; 
		cout<<minn<<" "<<maxn<<endl;
	} 
	return 0;
}
```
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