8 条题解

  • 6
    @ 2024-2-22 10:31:38
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	double Xa,Ya,Xb,Yb;
    	scanf("%lf%lf%lf%lf",&Xa,&Ya,&Xb,&Yb);
    	printf("%.3f",sqrt((Xb-Xa)*(Xb-Xa)+(Yb-Ya)*(Yb-Ya)));
    	return 0;
    }
    
    • 1
      @ 2025-3-31 20:37:32
      #include<bits/stdc++.h>
      using namespace std; 
      int main(){
      	double xa,ya,xb,yb,a;
      	cin>>xa>>ya>>xb>>yb;
      	a=sqrt((xa-xb)*(xa-xb)+(ya-yb)*(ya-yb));
      	printf("%.3lf",a);
      	return 0;
      }
      
      
      
      • 1
        @ 2024-2-22 11:21:36
        #include<bits/stdc++.h>
        using namespace std;
        int main()
        {
        	double Xa,Ya,Xb,Yb;
        	scanf("%lf%lf%lf%lf",&Xa,&Ya,&Xb,&Yb);
        	printf("%.3f",sqrt((Xb-Xa)*(Xb-Xa)+(Yb-Ya)*(Yb-Ya)));
        	return 0;
        }
        
        
        • 0
          @ 2025-2-19 12:29:04

          #include<bits/stdc++.h> using namespace std; int main() { double Xa,Ya,Xb,Yb; scanf("%lf%lf%lf%lf",&Xa,&Ya,&Xb,&Yb); printf("%.3f",sqrt((Xb-Xa)(Xb-Xa)+(Yb-Ya)(Yb-Ya))); return 0; }

          • 0
            @ 2024-2-22 10:03:52
            #include<bits/stdc++.h>
            using namespace std;
            int main()
            {
            	double Xa,Ya,Xb,Yb;
            	scanf("%lf%lf%lf%lf",&Xa,&Ya,&Xb,&Yb);
            	printf("%.3f",sqrt((Xb-Xa)*(Xb-Xa)+(Yb-Ya)*(Yb-Ya)));
            	return 0;
            }
            
            • 0
              @ 2024-2-22 9:57:42

              #include<bits/stdc++.h> using namespace std; int main(){ double Ya,Xa,Yb,Xb; scanf("%lf%lf%lf%lf",&Ya,&Xa,&Yb,&Xb); printf("%.3lf",sqrt((Xb-Xa)(Xb-Xa)+(Yb-Ya)(Yb-Ya))); }

              • -1
                @ 2024-2-22 9:57:47

                #include<bits/stdc++.h> using namespace std; int main(){ double Ya,Xa,Yb,Xb; scanf("%lf%lf%lf%lf",&Ya,&Xa,&Yb,&Xb); printf("%.3lf",sqrt((Xb-Xa)(Xb-Xa)+(Yb-Ya)(Yb-Ya))); return 0; }

                • -3
                  @ 2024-2-21 11:19:06

                  #include<bits/stdc++.h> using namespace std; int main() { double Xa,Ya,Xb,Yb; scanf("%lf%lf%lf%lf",&Xa,&Ya,&Xb,&Yb); printf("%.3f",sqrt((Xb-Xa)(Xb-Xa)+(Yb-Ya)(Yb-Ya))); return 0; }

                  • 1

                  信息

                  ID
                  80
                  时间
                  1000ms
                  内存
                  128MiB
                  难度
                  1
                  标签
                  (无)
                  递交数
                  317
                  已通过
                  229
                  上传者