17 条题解
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1
fs247zhangruiyi1 LV 3 @ 2024-11-19 16:10:01
#include<bits/stdc++.h> using namespace std; int main(){ int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; }
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0
rc2025guoyanshan LV 8 @ 2025-4-20 9:28:19
using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } -
-1
rc245zhangjiayi1 LV 5 @ 2024-2-22 11:19:51
#include<bits/stdc++.h> using namespace std; int main(){ int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } 是对的试过了😄 👍 👍 👍 👍
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-4
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-4
#include<bits/stdc++.h> using namespace std; int main(){ int a1,a2,n,c; cin>>a1>>a2>>n; c=(a2-a1)*n-(a2-a1-a1); cout<<c; return 0; }
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-4
rc247lijunhe1 LV 8 @ 2024-2-22 10:51:47
#include<bits/stdc++.h> using namespace std; int main(){ int a1,a2,n,c,d; cin>>a1>>a2>>n; c=a2-a1; d=a1+c*(n-1); cout<<d; }
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-5
rc246zhangyuqinheng1
LV 8
@ 2024-2-22 11:23:13
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差 -
-5
#include<bits/stdc++.h> using namespace std; int main(){ int a1,a2,b,c,n; cin>>a1>>a2>>b; c=a2-a1; n=a1+(b-1)*c; cout<<n; }
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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-6
#include<bits/stdc++.h> using namespace std; int main() { int a,b,n,c; cin>>a>>b>>n; c=b-a; n=a+(n-1)*c; cout<<n; return 0; } //首相+（项数减一）*公差
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