题目分析

输入字符串，分别输出字符串中字母和数字的个数。

代码实现

#include<cstdio>
int n=0,l=0;
int main(){
    char c;
	while((c=getchar())!=EOF){
    	if(c>='0'&&c<='9')n++;
    	else if((c>='a'&&c<='z')||(c>='A'&&c<='Z'))l++;
	}
    printf("Letters=%d\nDigits=%d\n",l,n);
    return 0;
}

记得给五星好评哦喵~ 谢谢客官啦~

#include <iostream>
using namespace std;
int main (){
    string s;
    cin>>s;
    int cnt1=0;
    int cnt2=0;
    int len=s.length();
    for(int i=0;i<len;i++){
         if((s[i]>='a' && s[i]<='z') ||     (s[i]>='A' && s[i]<='Z')) cnt1++;
         if(s[i]>='0' && s[i]<='9') cnt2++;
}
    cout<<"Letters="    <<cnt1<<endl;
    cout<<"Digits="<<cnt2;
    return 0;
}

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