10 条题解

  • 3
    @ 2024-3-17 7:49:00
    #include<bits/stdc++.h>
    #define int long long
    #define endl '\n' 
    using namespace std;
    int a[10000];
    string s1,s2,s3,s4;
    signed main(){
    
    	int a,b,c,d,n,m,i,s=0;
    	scanf("%d",&n);
    	for(i=1;i<=n;++i){
    		scanf("%d",&m);
    		a=m/1000;
    		b=(m/100)%10;
    		c=(m/10)%10;
    		d=m%10;
    		if(d-a-b-c>0){
    			s++;
    		}
    	}	
    	printf("%d\n",s);	
    	return 0;
    }
    
    • 1
      @ 2024-12-10 21:46:59

      • 0
        @ 2025-3-21 17:21:01

        #include<bits/stdc++.h> #define int long long #define endl '\n' using namespace std; int a[10000]; string s1,s2,s3,s4; signed main(){

        int a,b,c,d,n,m,i,s=0;
        scanf("%d",&n);
        for(i=1;i<=n;++i){
        	scanf("%d",&m);
        	a=m/1000;
        	b=(m/100)%10;
        	c=(m/10)%10;
        	d=m%10;
        	if(d-a-b-c>0){
        		s++;
        	}
        }	
        printf("%d\n",s);	
        return 0;
        

        }

        • 0
          @ 2024-4-19 16:50:03

          #include<bits/stdc++.h> using namespace std; int main(){ int n,x,y=0; cin>>n; for(int q=1;q<=n;q++){ cin>>x; if((x%10)-(x/100%10)-(x/10%10)-(x/1000%10)>0){ y++; } }cout<<y; return 0; }

          • 0
            @ 2024-4-8 20:27:01
            #include<bits/stdc++.h>
            #define int long long
            #define endl'\n' 
            using namespace std;
            int a[10000];
            string s1,s2,s3,s4;
            signed main(){
            	int a,b,c,d,n,m,s=0;
            	scanf("%d",&n);
            	for(int i=1;i<=n;i++){
            		scanf("%d",&m);
            		a=m/1000;
            		b=(m/100)%10;
            		c=(m/10)%10;
            		d=m%10;
            		if(d-a-b-c>0){
            			s++;
            		}
            	}	
            	printf("%d\n",s);	
            	return 0;
            }
            
            • 0
              @ 2024-3-10 10:36:31
              #include<bits/stdc++.h>
              #define int long long
              #define endl '\n' 
              using namespace std;
              int a[10000];
              string s1,s2,s3,s4;
              signed main(){
              
              	int a,b,c,d,n,m,i,s=0;
              	scanf("%d",&n);
              	for(i=1;i<=n;++i){
              		scanf("%d",&m);
              		a=m/1000;
              		b=(m/100)%10;
              		c=(m/10)%10;
              		d=m%10;
              		if(d-a-b-c>0){
              			s++;
              		}
              	}	
              	printf("%d\n",s);	
              	return 0;
              }
              
              • 0
                @ 2024-2-15 10:26:56
                #include<bits/stdc++.h>
                #define int long long
                #define endl '\n' 
                using namespace std;
                int a[10000];
                string s1,s2,s3,s4;
                signed main(){
                
                	int a,b,c,d,n,m,i,s=0;
                	scanf("%d",&n);
                	for(i=1;i<=n;++i){
                		scanf("%d",&m);
                		a=m/1000;
                		b=(m/100)%10;
                		c=(m/10)%10;
                		d=m%10;
                		if(d-a-b-c>0){
                			s++;
                		}
                	}	
                	printf("%d\n",s)	
                	return 0;
                }
                
                • -1
                  @ 2024-4-7 17:42:00
                  1. #include<bits/stdc++.h> using namespace std; int main(){ int n,a,g,s,b,q,cnt=0; cin>>n; for(int i = 1;i<=n;i++){ cin>>a; g = a%10; s = a/10%10; b = a/100%10; q = a/1000; if(g-q-b-s>0){ cnt++; } } cout<<cnt; return 0; } 纯手工无添加
                  • -1
                    @ 2024-3-24 11:24:32

                    #include<bits/stdc++.h> #define int long long #define endl '\n' using namespace std; int a[10000]; string s1,s2,s3,s4; signed main(){

                    int a,b,c,d,n,m,i,s=0;
                    scanf("%d",&n);
                    for(i=1;i<=n;++i){
                    	scanf("%d",&m);
                    	a=m/1000;
                    	b=(m/100)%10;
                    	c=(m/10)%10;
                    	d=m%10;
                    	if(d-a-b-c>0){
                    		s++;
                    	}
                    }	
                    printf("%d\n",s);	
                    return 0;
                    

                    }

                    • -1
                      @ 2024-3-17 10:43:54

                      #include<bits/stdc++.h> using namespace std; int main(){ int n,i=1,sum=0,o; cin>>n; while(i<=n){ i++; cin>>o; if(o%10-o/10%10-o/100%10-o/1000%10>0){ sum=sum+1; } } cout<<sum; return 0; }

                      • 1

                      信息

                      ID
                      1242
                      时间
                      1000ms
                      内存
                      128MiB
                      难度
                      3
                      标签
                      (无)
                      递交数
                      382
                      已通过
                      214
                      上传者